Round Robin Tournament Scheduling
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91
Requests / Re: 8 men 8 woman, Rotating Partner Mixed Round Robin
« Last post by Ian Wakeling on November 22, 2024, 03:40:59 AM »
This is the best schedule that I have for 8 rounds:

(m06 f08 v m02 f03) (m01 f05 v m04 f06) (m03 f07 v m05 f02) (m08 f01 v m07 f04)
(m01 f08 v m07 f01) (m08 f05 v m05 f03) (m03 f02 v m06 f04) (m02 f06 v m04 f07)
(m02 f05 v m08 f02) (m04 f01 v m05 f04) (m07 f07 v m06 f03) (m01 f06 v m03 f08)
(m04 f03 v m01 f02) (m03 f05 v m07 f08) (m05 f01 v m06 f06) (m02 f07 v m08 f04)
(m08 f03 v m03 f06) (m07 f05 v m06 f07) (m04 f04 v m05 f08) (m02 f02 v m01 f01)
(m05 f07 v m01 f03) (m04 f05 v m03 f01) (m02 f04 v m07 f06) (m08 f08 v m06 f02)
(m07 f02 v m05 f06) (m04 f08 v m08 f07) (m03 f03 v m02 f01) (m01 f04 v m06 f05)
(m01 f07 v m03 f04) (m04 f02 v m07 f03) (m05 f05 v m02 f08) (m08 f06 v m06 f01)

It does contain all male/female partnerships exactly once, however the opposition pairings are not optimal.  In particular the following four pairs never oppose (m1 m8) (m4 m6) (f1 f7) (f3 f4).  Hope that helps.
92
Requests / Re: 8 men 8 woman, Rotating Partner Mixed Round Robin
« Last post by Philly617 on November 21, 2024, 01:58:40 PM »
Ian, I did see that post, #8 as I don't have any situation where we are avoiding a spouse.

Was wondering why there were 9 rounds in that scenario.

With 8 men and 8 women.  I'm looking for 8 round scenario where each male plays with each female once?  Is that covered in your 9 rounds scenario and one of the round is duplicative and I just need to delete it?

Appreciate your help.
93
Requests / Re: 8 men 8 woman, Rotating Partner Mixed Round Robin
« Last post by Ian Wakeling on November 21, 2024, 03:39:59 AM »
See here for a similar question.

and consider replies #1 or #8 here for 7 or 9 round schedules.  The first is spouse avoiding so there is one other opposite sex player who you never meet.

94
Requests / 8 men 8 woman, Rotating Partner Mixed Round Robin
« Last post by Philly617 on November 21, 2024, 12:23:48 AM »
I'm new to this site but am trying to figure out schedule for below format.

- 8 men
- 8 women
- Each person plays with every mixed partner which means 8 games
- playing on 4 courts
- How do I best randomize games so each person plays against everyone else and not playing the same person 3 or 4 times
95
Requests / Re: variation on a steiner triple system
« Last post by babyteeth on November 18, 2024, 03:13:49 PM »
As I was posting this, I had another thought which may be relevant. If this got bigger, I would necessarily organize this into brackets. So within bracket groupings, I would want those conditions, but no need for that across all tournament participants.
96
Requests / Re: variation on a steiner triple system
« Last post by babyteeth on November 18, 2024, 03:09:43 PM »
This is very interesting, thank you! With only 18ppl at the moment, I don't know how I would compensate for so many 'ghost' players. Also, much of that math is well over my head 🤓
Perhaps I'm overthinking. I'd very much appreciate any suggestions you may have in how to approach this. I have a group of people who all play the same game, of which 10-30 of those might sign up for a tournament. It's teams of 3 vs 3, but everyone plays as individuals. Each individual player on a team gets 3 pts for the team win, 1 for team draw, 0 for team loss.
Top 6 players in points move on to a set of 3 finals matches with teams based on rank (1-6) after round one

I'm trying to find a way to assign players so that a) teams are as unique as possible. b) opponents are unique as possible. c) the system is flexible if there are odd numbers of participants. d) everyone plays the same number of matches. And e) minimizing the total number of matches, no matter how many players sign up within that range.
Also, this is a video game, so there are 'infinite' courts!

Please let me know what you think. Thank you in advance!
BT
97
Requests / Re: Mixed Doubles, rotating partners and opponents, 16 players, 8 rounds, no repeat
« Last post by Ian Wakeling on November 17, 2024, 01:16:36 PM »
It can be done on 3 courts with some byes, but I am not aware of a 4 court solution.  See the schedule in reply #6 here.
98
Requests / Re: variation on a steiner triple system
« Last post by Ian Wakeling on November 17, 2024, 01:09:36 PM »
I don't think a generalizable solution exists, however what you are asking for is close to a resolvable covering.  For example see Table A.2 in this paper can potentially be converted to a minimum round schedule for 24 players on 4 courts of 3 vs 3, where all pairs of players meet at least once (either as partners or opponents).
99
Requests / Re: Bridge tables arrangement
« Last post by Ian Wakeling on November 17, 2024, 12:47:30 PM »
Click on the link at the top of the page that says "Visit the pages that inspired the forum.." then go for cyclic tables, where the cyclic or balanced table for 12 items should give you what you want.  Hope that helps.
100
Requests / variation on a steiner triple system
« Last post by babyteeth on November 15, 2024, 07:19:17 PM »
Hi there!
I have a scenario for which I cannot find a representative solution and I could use your help!
I have a group of players who want to play in a 3v3 tournament, and we want to arrange each player into rotating groups of three such that every player will play the same number of matches, play either with -or- against every other player at least once, AND minimize the total number of matches.
The current number of players is 18, but will change for each tournament, so I am looking for a generalizable solution as opposed to brute force.
Please let me know if there is any information required that I have left out. Thank you!
BT
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