Round Robin Tournament Scheduling

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71
Requests / Re: Round robin rotating partners
« Last post by Ian Wakeling on January 28, 2024, 04:28:07 AM »
I think the schedule below will work for you.  Everyone has 6 different partners, plays against 4 members of the other team once, and plays against the other 4 members twice.

(CA3 CA1 v US2 US6) (CA5 CA4 v US1 US5) (CA7 CA2 v US7 US8) (CA8 CA6 v US3 US4)
(CA8 CA5 v US5 US6) (CA2 CA4 v US7 US4) (CA7 CA3 v US1 US2) (CA1 CA6 v US8 US3)
(CA2 CA8 v US2 US3) (CA6 CA7 v US7 US5) (CA1 CA5 v US1 US4) (CA4 CA3 v US6 US8)
(CA1 CA2 v US5 US3) (CA6 CA4 v US2 US7) (CA3 CA8 v US1 US8) (CA7 CA5 v US4 US6)
(CA6 CA2 v US1 US6) (CA8 CA7 v US4 US2) (CA3 CA5 v US3 US7) (CA4 CA1 v US8 US5)
(CA3 CA2 v US4 US5) (CA5 CA6 v US2 US8) (CA8 CA1 v US7 US6) (CA4 CA7 v US1 US3)
72
Requests / Round robin rotating partners
« Last post by DSpb69801 on January 28, 2024, 02:45:53 AM »
I am setting up a round robin pickleball tournament with Canadian players against US players.  There will be 8 Canadians and 8 US players, playing 6 rounds on 4 courts.  Would like partners to rotate after each round and play as many different opponents as possible but keeping Canadians playing against Americans.  Thank you!

73
Requests / Re: Round Robin - 8 Player Doubles
« Last post by Ian Wakeling on January 27, 2024, 09:08:57 AM »
I am doing better with your latest request if I start with the schedule from reply #14 above.  Then I can get a skill score of 116, where the last round is 'ranked'.

 2 10 12  6
 2 12 10  6
11  1  7  5
11  7  1  5
 9  8  4  3
 9  3  8  4
10  8  3  5
10  5  3  8
 4 12  7  1
 4  7 12  1
 9  6 11  2
 9 11  2  6
 8 11  6  1
 8  6 11  1
 2 12  7  3
 2  7  3 12
 9  5  4 10
 9  4 10  5
11  5  4 12
11  4  5 12
10  3  7  6
10  7  6  3
 9  1  2  8
 9  2  8  1
 4  1  2  3
 4  2  1  3
 8  7  5  6
 8  5  7  6
 9 10 11 12
 9 12 10 11

hope that is of some use.
74
Requests / Re: Mix double 12 schedule
« Last post by Ian Wakeling on January 27, 2024, 08:37:40 AM »
I believe that no 6 round schedule exists that meets your partner once and pair once criteria.  However, the 7 round schedule below has partners once or twice, and opponents once or twice.  Hope that helps.

(m6 f1 v m1 f6) (m3 f2 v m2 f4) (m5 f3 v m4 f5)
(m1 f2 v m3 f3) (m6 f4 v m5 f1) (m4 f5 v m2 f6)
(m4 f6 v m1 f4) (m5 f5 v m6 f2) (m3 f1 v m2 f3)
(m2 f6 v m5 f3) (m1 f1 v m4 f2) (m6 f5 v m3 f4)
(m5 f4 v m1 f3) (m4 f1 v m3 f5) (m6 f6 v m2 f2)
(m6 f2 v m4 f3) (m2 f5 v m1 f4) (m3 f1 v m5 f6)
(m3 f6 v m6 f3) (m5 f2 v m1 f5) (m2 f1 v m4 f4)
75
Requests / Mix double 12 schedule
« Last post by travbanan on January 26, 2024, 06:41:09 PM »
I need schedule for mixed doubles padel round robin for 12 players (6 men and 6 women) where each man pairs with each women once and against each other once or so close to this as possible. We have 3 court and 6-7 rounds

Anyone have one?
76
Requests / Re: 6 courts with 28 players
« Last post by Ian Wakeling on January 26, 2024, 03:36:23 AM »
How many rounds are you wanting to play?  Good choices would be 7, 14, 21,...  rounds as then everyone could have the same number of byes. For example 7 rounds with 4 byes per round, is 28 byes enough that everyone can have exactly one bye.
77
Requests / 6 courts with 28 players
« Last post by RayG195 on January 25, 2024, 03:47:38 PM »
Trying to get a schedule for 6 courts with 28 players for pickleball. I am good through 27 players, but then my current schedule bumps to 7 courts and we only have 6.
78
Requests / Re: badminton tournamount
« Last post by Ian Wakeling on January 23, 2024, 02:55:48 PM »
I had not seen plan2play before so I took a quick look, and I ended up with a schedule where one of the 20 players had 9 others players who they never played with either as partners or opponents.  It's possible to do a lot lot better and I offer the schedule below which gives you everything that you asked for except for the fact that players 15 & 19 oppose twice. 

(10  3 v  7 14)  ( 9 11 v  2  1)  (13 15 v  5 12)  ( 8  6 v  4 16)
(17  5 v 19  9)  ( 4 11 v  7 10)  (12  1 v  3  6)  ( 2 18 v 20  8)
( 7 20 v 17  6)  ( 8 14 v 19  1)  ( 4  5 v 16 18)  (15  3 v  2 13)
(16 12 v  9  2)  ( 1  3 v 18 17)  ( 4 19 v 15 11)  (14 10 v 20 13)
(10 12 v  8 18)  ( 9  6 v 14 19)  (20 11 v  5 15)  (17  7 v 16 13)
( 9  8 v 15  7)  (12 13 v  1  4)  ( 5  2 v 10  6)  ( 3 14 v 16 11)
(17 11 v  6 12)  ( 5 20 v  8  1)  (10  4 v  9  3)  ( 7 18 v 19  2)
(17  3 v  8  5)  (15 18 v 14  6)  (13 19 v  2 16)  ( 7  4 v 20  1)
(17  2 v  4 14)  (15  1 v 16 10)  ( 3 12 v 20 19)  ( 9 18 v 13 11)
(12 14 v  5  7)  (20 18 v  9 16)  (11  6 v 13  8)  (17 19 v 10 15)

The byes have a pattern to them 17,18,19,20 in round 1, 13,14,15,16 in round 2, etc..  Hope that helps.
79
Requests / Re: 2 teams of 5 players
« Last post by Ian Wakeling on January 23, 2024, 01:17:58 PM »
My guess is that this is impossible.  You could take the 10 player schedule in reply#3 here and rearrange the four players in each game so that it is two H players vs two W players.  This will give you some of what you want apart from the having one missing opposition player.
80
Requests / 2 teams of 5 players
« Last post by rowanklein on January 22, 2024, 06:17:00 PM »
Have a scenario where there are 2 teams of 5 players. 

Teams
HA, HB, HC, HD & HE
AA, AB, AC, AD & AE

Games are played in pairs from same team, against pair from other team.

Constraints.
- Play with each partner once (4 games each, 5 rounds including bye)
- Play against each opposition at least once, but not more than twice. 

Is there a soultion for this?