Round Robin Tournament Scheduling

Recent Posts

1
Comments and Thanks / Printing
« Last post by Angelo on January 16, 2020, 08:16:53 AM »
How can I print a round robing chart 
2
Requests / Re: Catan league. 4 player matches, 6 matches each, 10 player league
« Last post by ringcinema on January 11, 2020, 03:48:49 PM »
I see what you were saying now. No two games have completely different sets of players, so no two games can be played at the same time. That's novel.
3
Requests / Re: 14 Player Euchre Rotation
« Last post by Ian Wakeling on January 10, 2020, 06:02:34 AM »
There is a schedule here for 7 rounds and it links to another with 14 rounds.  I think one of those should work for you.
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Requests / 14 Player Euchre Rotation
« Last post by stef16 on January 09, 2020, 01:05:03 PM »
I am trying to figure out a 14 player Euchre Round Robin Rotation.  Everyone plays with a different partner.  Everyone sits twice.  Is this possible?
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Requests / Re: Catan league. 4 player matches, 6 matches each, 10 player league
« Last post by ringcinema on January 08, 2020, 11:27:47 AM »
I was unaware of this book. Many thanks.
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Requests / Re: Catan league. 4 player matches, 6 matches each, 10 player league
« Last post by Ian Wakeling on January 08, 2020, 10:55:53 AM »
It depends on what you mean by unique.  If the order in which the 15 games are played is ignored, and the many possible permutations of player numbers is ignored, then there are 3 different solutions. They are given in full on p29 of the Handbook of Combinatorial Designs, 2nd edition.
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Requests / Re: Catan league. 4 player matches, 6 matches each, 10 player league
« Last post by ringcinema on January 08, 2020, 10:34:01 AM »
Yes, thank you. You made short work of it. Is it true that there is a unique solution for this particular form?
8
Requests / Re: Whist style tourney
« Last post by Ian Wakeling on January 08, 2020, 06:11:03 AM »
It would be much better to have 10 weeks, then each player can have exactly 2 bye rounds, and exactly 8 games.  For example:

( 5  6 v  8  9)  (4  3 v 2 10)  (1  7)
( 1  7 v  9 10)  (5  4 v 3  6)  (2  8)
( 2  8 v 10  6)  (1  5 v 4  7)  (3  9)
( 3  9 v  6  7)  (2  1 v 5  8)  (4 10)
( 4 10 v  7  8)  (3  2 v 1  9)  (5  6)
   
( 8 10 v  9  5)  (1  6 v 4  2)  (3  7)
( 9  6 v 10  1)  (2  7 v 5  3)  (4  8)
(10  7 v  6  2)  (3  8 v 1  4)  (5  9)
( 6  8 v  7  3)  (4  9 v 2  5)  (1 10)
( 7  9 v  8  4)  (5 10 v 3  1)  (2  6)

Leave out the last round if 9 rounds is a hard limit for you, however only players 2 and 6 will have 8 games, the rest of the players will only have 7 games.
9
Requests / Re: Catan league. 4 player matches, 6 matches each, 10 player league
« Last post by Ian Wakeling on January 08, 2020, 05:57:53 AM »
Yes, this is possible, but the 15 games all have to be played at different times.  For example:


 5  3  2  7
 8  4  2  9
 3  1  6  8
 9  7  4  1
 8  5  4 10
 6  2  3  4
 1  5  9  6
 3 10  1  4
 9  8  3  5
 1  2  8  7
 4  6  7  5
 7  8  6 10
 2 10  5  1
10  7  9  3
 6  9 10  2


10
Requests / Catan league. 4 player matches, 6 matches each, 10 player league
« Last post by ringcinema on January 07, 2020, 03:35:15 PM »
It seems that it should be solvable to have each of the 10 players meet every other player exactly twice in the course of 6 matches of four players each. That's 6 matches with 3 opponents per player, with 9 others in the league meeting each one twice. 9*2 = 6*3.

So far, I'm only coming close. Perhaps there's only one solution?