Round Robin Tournament Scheduling

2v2 12 players, everyone plays each other at least once

mccjamb · 4 · 98

mccjamb

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Hi, I couldn't find this solution elsewhere on the forum and unfortunately I couldn't get the workbook to open for me (user error on my part I'm sure).  So, any way you have a solution for 12 players play against each other only once, on 3 courts?  No limit on rounds, but fewer the better.

Thanks!
« Last Edit: March 11, 2021, 09:57:05 AM by mccjamb »


Ian Wakeling

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Reply #1 on: March 11, 2021, 12:44:06 PM
You can simply slice up the standard round-robin for 12 players.   So starting with the balanced schedule here, play 'Match 1', 'Match 2', 'Match 3' as a sub-round on the 3 courts, then play 'Match 4', 'Match 5' and 'Match 6' as a new sub-round on the same 3 courts.  So you will need 22 rounds to complete the round-robin.


pbails

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Reply #2 on: March 16, 2021, 10:04:17 AM
Ian, is your answer different if the format is 2v2? 


Ian Wakeling

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Reply #3 on: March 17, 2021, 11:15:49 AM
Apologies, my solution above is wrong. I read the OP's message and not the title!  As the format is doubles play it becomes a harder problem. I have recently shown a solution for 16 players where a minimal 8 round solution is possible.  Unfortunately this will not work for 12 players as the corresponding spouse avoiding schedule does not exist.  Clearly a whist schedule exists with 11 rounds and all opponents exactly twice, wether the minimal solution in 6 rounds is possible, I don't know.