Yes this is possible, but there will be four pairs of teams who see each other three times, below these are (1 7), (2 4), (3 8) & (5 6)
(6 2 5 4) (7 1 3 8)
(2 3 7 6) (1 4 8 5)
(5 6 1 7) (3 8 4 2)
(4 7 2 1) (8 5 6 3)
If you have prior information on team ability, then you could make sure that closely matched teams were the ones that meet three times.