Recent Posts

31

Requests / Re: 21 person euchre rotation table

« Last post by Ian Wakeling on February 27, 2025, 04:23:09 AM »

Sorry, should have explained about that.  Start with the "solution for 13 players" which has the full schedule - note that player zero has the bye in round 1 and that the rounds are generated from the first round by cycling through the numbers 0 to 12 and then back to 0.  For 21 players all you are given is the first round, so you need add zero for the bye and then cycle through 0 to 20, generating  a total of 21 rounds.

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Requests / Re: 21 person euchre rotation table

« Last post by kslates on February 26, 2025, 08:36:27 AM »

I am not sure how to use that chart. Nowhere does it have #21 in the rotation

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Requests / Re: 21 person euchre rotation table

« Last post by Ian Wakeling on February 25, 2025, 05:45:23 PM »

You could look here for "21 players".  I think you need 21 rounds as every round one of the 21 players has  a bye.

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Requests / 21 person euchre rotation table

« Last post by kslates on February 25, 2025, 01:21:53 PM »

I am having a euchre party Saturday with 11 couples, but one person does not play euchre. So is it possible to have a 21 person rotation where everyone plays with everyone and against everyone if possible. So I would need 20 rounds. Thanks!

35

Requests / Re: Partitioned Balanced Tournament Design (PBTD) for 8 teams with more venues

« Last post by Innesw20 on February 24, 2025, 05:33:07 PM »

Thanks Ian, they solve my problem.

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Requests / Re: PBTD for 8 teams with more venues

« Last post by Ian Wakeling on February 22, 2025, 12:13:45 AM »

The more venues there are, the easier things get.  With 6 venues you can have:

(H A) (---) (F G) (B C) (---) (D E)
(---) (H B) (---) (F E) (D G) (A C)
(E G) (D F) (H C) (---) (A B) (---)
(---) (A E) (---) (H D) (F C) (B G)
(F B) (C G) (D A) (---) (H E) (---)
(D C) (---) (B E) (A G) (---) (H F)

which leaves the following 4 pairings to be played in the final round.

(A F) (B D) (C E) (G H)


If you have 7 venues, then there is the Room Square.

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Requests / Re: PBTD for 8 teams with more venues

« Last post by Innesw20 on February 21, 2025, 05:43:10 PM »

Afraid not - it does need to be partitioned: a team at a venue at most once in rounds 1-4 and at most once in rounds 4-7.

I imagine it would look something like this, if it can work for 5 venues (rounds in rows, venues in cols):
(   ) (1 x) (x x) (x x) (x x)
(x x) (x x) (   ) (x x) (1 x)
(x x) (   ) (1 x) (x x) (x x)
(1 x) (x x) (x x) (x x) (   )
(x x) (x x) (1 x) (   ) (x x)
(x x) (   ) (x x) (x x) (1 x)
(   ) (x x) (x x) (1 x) (x x)
Ideally each team should play on each venue at least once in the competition, but that may be asking too much.

38

Requests / Re: PBTD for 8 teams with more venues

« Last post by Ian Wakeling on February 21, 2025, 04:02:01 AM »

The PBTD might not be necessary.  Could you use the regular balanced schedule instead.  Go here and enter 8 items and 'balanced'.

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Requests / Partitioned Balanced Tournament Design (PBTD) for 8 teams with more venues

« Last post by Innesw20 on February 20, 2025, 05:58:32 AM »

In the game of lawn bowls, if there are only 8 teams in a competition there would frequently be more rinks available (the standard green has eight) than are required to play each round (4).

The mathematicians have shown that there does not exist a PBTD for 8 teams and 4 venues.

I was wondering whether a PBTB-equivalent for 8 teams could be constructed where the number of venues is 5 instead of 4? If not, would 6 venues allow it? Or is it just not mathematically possible? This is essentially easing the restriction on the number of venues that applies in the standard definition of PBTDs.

40

Requests / Re: 16 Players Foursomes League

« Last post by Ian Wakeling on February 20, 2025, 03:03:37 AM »

Please see reply #1 that I wrote here.  It will give you both 10 and 15 rounds and more if you want.  Note that the 16 players are numbered zero to 15.