Dwayne,
Using a computer search I can find solutions to this problem where only one pair of teams occur twice together. In the schedule below the repeated pair is (3 8).
Time St1 St2 St3 St4 St5
1 (2 4) (5 6) (1 7) (3 8) - -
2 (1 3) (4 7) (5 8) - - (2 6)
3 (6 8) (1 2) - - (4 5) (3 7)
4 (5 7) - - (2 3) (1 6) (4 8)
5 - - (3 8) (4 6) (2 7) (1 5)
Let me know if this works for you.
If you only had 4 stations and 4 timeslots then this would correspond to half of a round-robin tournament design and solutions would be much easier to find.
Regards,
Ian.
Saturday, November 26 2005, 09:23 am