Round Robin Tournament Scheduling
Schedules - You must register to Post and Download => Requests => Topic started by: xxyyzz on February 15, 2013, 10:27:31 AM
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How can I schedule 10 golfers over 7 rounds, so everyone is with everyone else the same number of times.
The configuration can be 4 4 2 or 4 3 3 which ever works out better
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I think 4 3 3 is the best format. For example:
( 1 4 3 7) (9 8 6) (5 2 10)
( 6 9 2 4) (1 5 3) (8 7 10)
( 4 5 8 10) (6 2 1) (3 9 7)
( 6 4 10 3) (2 8 1) (7 5 9)
( 10 9 2 3) (8 1 4) (6 5 7)
( 7 10 6 1) (3 2 8) (9 4 5)
( 5 6 8 3) (4 7 2) (1 9 10)
Above players 3,4,6 & 10 have 4 foursomes and 3 threesomes (all 9 opponents exactly twice each), while the other 6 players have 2 foursomes and 5 threesomes (7 opponents twice each and 2 opponents only once).
Hope that helps.
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Thnaks.
I just found out that one of rounds is not happening.. so we r only doing 6 rounds.. does that change things?
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The best solution for 6 rounds is to have one golfer (player 10) who always plays in the foursome and who has all 9 opponents exactly twice.
Below players 1 to 9 all have exactly 2 games in foursomes and 4 games in threesomes with all opponents either once or twice (4 of them once and 5 of them twice).
(10 9 5 6) (3 4 2) (7 8 1)
(10 7 6 4) (1 5 3) (8 9 2)
(10 8 4 5) (2 6 1) (9 7 3)
(10 8 3 2) (4 1 6) (9 7 5)
(10 9 1 3) (5 2 4) (7 8 6)
(10 7 2 1) (6 3 5) (8 9 4)