Round Robin Tournament Scheduling

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61
Requests / Re: Uno Tournament 6
« Last post by schmidthaus on February 11, 2024, 04:33:31 PM »
Actually yes, I have more than enough uno versions for a 7th table!  And it doesn't matter to me how many people per table as long as it is relatively close (like we wouldn't want 2 people at one table and another have 6).  

I hadn't thought about the 'bye' idea.  We've had 'bye' player numbers when someone no-shows at the last minute (grrr).  If a different solution isn't available, then the bye is a viable option as long as everyone has the same number of byes since they will be scored.  
62
Requests / Re: Uno Tournament 6
« Last post by Ian Wakeling on February 11, 2024, 12:18:19 PM »
I have another idea.  A lot of the difficulty here is specifically because you have 6 tables, and this is just a difficult number to work with.  Are you able to find a 7th version of Uno?  If you can that's great, or if not still have 7 tables, but assign the last one as a bye, so it becomes the drinks and snacks table.  Now you can use the following:

(1  8 15 22 29 36) (2 10 18 26 34 42) (3 12 21 23 32 41) (4 14 17 27 30 40) (5  9 20 24 35 39) (6 11 16 28 33 38) (7 13 19 25 31 37)
(2  9 16 23 30 37) (3 11 19 27 35 36) (4 13 15 24 33 42) (5  8 18 28 31 41) (6 10 21 25 29 40) (7 12 17 22 34 39) (1 14 20 26 32 38)
(3 10 17 24 31 38) (4 12 20 28 29 37) (5 14 16 25 34 36) (6  9 19 22 32 42) (7 11 15 26 30 41) (1 13 18 23 35 40) (2  8 21 27 33 39)
(4 11 18 25 32 39) (5 13 21 22 30 38) (6  8 17 26 35 37) (7 10 20 23 33 36) (1 12 16 27 31 42) (2 14 19 24 29 41) (3  9 15 28 34 40)
(5 12 19 26 33 40) (6 14 15 23 31 39) (7  9 18 27 29 38) (1 11 21 24 34 37) (2 13 17 28 32 36) (3  8 20 25 30 42) (4 10 16 22 35 41)
(6 13 20 27 34 41) (7  8 16 24 32 40) (1 10 19 28 30 39) (2 12 15 25 35 38) (3 14 18 22 33 37) (4  9 21 26 31 36) (5 11 17 23 29 42)
(7 14 21 28 35 42) (1  9 17 25 33 41) (2 11 20 22 31 40) (3 13 16 26 29 39) (4  8 19 23 34 38) (5 10 15 27 32 37) (6 12 18 24 30 36)


This has best possible mix of players and it also has the property that it will work no matter how many players turn up (between 14 and 42).  Simply delete the unused player numbers from the schedule above.
63
Requests / Re: Uno Tournament 6
« Last post by schmidthaus on February 11, 2024, 10:44:48 AM »
It is, thank you!  You understood my predicament well.  As you surmised, there will have to be a compromise of mixing of players, and I'm good with that.  The party currently has 34 RSVPs, I will ask for recommitments a week out where I expect the number to drop, and then day of experience tells me that there will be a couple more drops.  

Because every table features a different version of Uno (Classic, Attack, Flip, Spin....you'd be surprised how many there are!) it is most important that everyone gets a chance to play every kind.  

What I chiefly want to avoid is what happened last year - I tried using a round-robin generator that is mainly used for baseball tournaments.  Each table was a "field" and I told it each field had 3 games each day, with no team playing twice in the same day (yielding 6 teams = 6 players at the table) and limited the number of weeks to the number of rounds just based on my experience of duration of the party.  

At a glance, this seemed to work but in execution, there was a problem.  It seems the generator had also assigned a home-field to teams.  We had a player that it turned out that 6 of 9 games he was at the red table and did not get to play all the different versions.  Some players had this happen to a lesser degree.  

So thank you for the above schedules that favor the table rotation first!  Thank you so much for your help!!
64
Requests / Re: King/Queen of the Beach
« Last post by Ian Wakeling on February 10, 2024, 03:50:29 AM »
I have answered your question here.
65
Requests / Re: Mix double 12 schedule
« Last post by Ian Wakeling on February 10, 2024, 03:41:57 AM »
The schedule below does balance the male-female partnerships, but at the expense of the imbalance of the opposition pairs.  Each player has one opposite sex player who they never oppose, and two other players who they oppose twice. For example, consider M1: the pair (M1 F3) never oppose, while (M1 M4) & (M1 F4) oppose twice.  Hope that helps.

[(M2 F4):(M5 F3)] [(M6 F2):(M3 F6)] [(M1 F5):(M4 F1)]
[(M5 F6):(M4 F5)] [(M3 F4):(M1 F2)] [(M2 F3):(M6 F1)]
[(M5 F1):(M6 F6)] [(M3 F2):(M4 F3)] [(M2 F5):(M1 F4)]
[(M2 F6):(M3 F5)] [(M1 F1):(M5 F2)] [(M4 F4):(M6 F3)]
[(M1 F6):(M6 F4)] [(M5 F5):(M3 F3)] [(M4 F2):(M2 F1)]
[(M5 F4):(M3 F1)] [(M4 F6):(M1 F3)] [(M2 F2):(M6 F5)]
66
Requests / Re: Mix double 12 schedule
« Last post by kitch3 on February 09, 2024, 03:34:16 PM »
Could you modify it so there is only 6 rounds and every male plays once with every female 
67
I am aware that you can have a balanced solution for 16 players and 30 games of 4 vs 4.


  ( 5  1 14  9 v 16  7  4  8) ( 3 15 13  6 v  2 10 11 12)
  ( 6  2 15 10 v 16  8  5  9) ( 4  1 14  7 v  3 11 12 13)
  ( 7  3  1 11 v 16  9  6 10) ( 5  2 15  8 v  4 12 13 14)
  ( 8  4  2 12 v 16 10  7 11) ( 6  3  1  9 v  5 13 14 15)
  ( 9  5  3 13 v 16 11  8 12) ( 7  4  2 10 v  6 14 15  1)
  (10  6  4 14 v 16 12  9 13) ( 8  5  3 11 v  7 15  1  2)
  (11  7  5 15 v 16 13 10 14) ( 9  6  4 12 v  8  1  2  3)
  (12  8  6  1 v 16 14 11 15) (10  7  5 13 v  9  2  3  4)
  (13  9  7  2 v 16 15 12  1) (11  8  6 14 v 10  3  4  5)
  (14 10  8  3 v 16  1 13  2) (12  9  7 15 v 11  4  5  6)
  (15 11  9  4 v 16  2 14  3) (13 10  8  1 v 12  5  6  7)
  ( 1 12 10  5 v 16  3 15  4) (14 11  9  2 v 13  6  7  8)
  ( 2 13 11  6 v 16  4  1  5) (15 12 10  3 v 14  7  8  9)
  ( 3 14 12  7 v 16  5  2  6) ( 1 13 11  4 v 15  8  9 10)
  ( 4 15 13  8 v 16  6  3  7) ( 2 14 12  5 v  1  9 10 11)

There might be something similar for 18 players and 51 games of 3 vs 3, and 20 players and 38 games of 5 vs 5.
68
Requests / Re: King/Queen of the Beach
« Last post by kitch3 on February 09, 2024, 12:39:41 PM »
Ian could you possibly set this same format up with 6 guys and 6 gals but on three nets instead of two? And only 6 rounds instead of 7
69
I was looking for a greater than 13 (detailed elsewhere) single court configurations with reasonable balance on played with/against if anyone has come across or figured out such combinations.
70
Requests / Re: Uno Tournament 6
« Last post by Ian Wakeling on February 05, 2024, 02:49:51 PM »
I am not aware of any resource that may provide useful schedules here.  Actually your scheduling problem is not easy because there is a trade off between playing each type of Uno once, and having a good mix of players.  As your priority is clearly the former, the mix of players must necessarily be compromised.  I can perhaps make a few schedules, but it sounds like you will not know the final number until the last minute, so I am not sure how much help I can be.

Here is an example.  Let's say you have 30 people and want 6 rounds of play with 6 tables of 5.  The following schedule might work:

        Table 1          Table 2          Table 3          Table 4          Table 5          Table 6
 R1 (10  6 18  3 12) ( 2 13 15 26 11) (14 23  7 22  5) ( 1 20  4 17 25) (21 16 19  8 27) (28 24 30  9 29)
 R2 (27  1 19 14  2) ( 7 10  8  9 28) (16 24  3 13 25) (30  6 22 11 15) (20 29 17 12  5) (23 21  4 26 18)
 R3 ( 9 15 22 26 16) (30 25 18 17 14) (19 29 10  4 11) (24 27 23 21 12) ( 6 13 28  1  7) ( 3  8  5 20  2)
 R4 (24 17  4  7  8) ( 3 22  1 21 29) (15 27 18 20 28) ( 5 26 13 19  9) (23 30 25 10  2) (11 16 14  6 12)
 R5 (11 28 25 21  5) (23 19 20  6 24) (26 12  8  1 30) ( 2  7 29 16 18) ( 4  9 14  3 15) (13 27 22 10 17)
 R6 (29 23 13 30 20) (27 12  4 16  5) ( 6  9 17 21  2) (28  3  8 14 10) (24 18 22 26 11) (15 25  1 19  7)

Above the players occur exactly once in each round/row and exactly once on each table.  No pair of players sit together at a table more than twice. Although it varies from player to player, each player will have some others whom they never meet, and a few players who they meet twice.  Does that seem useful?