Hello,
I know, there's a solution of 36 Players playing in foursomes in 11 rounds. Every Player won't Play two Other Players.
Is there a possibility, that theese missing pairings are groups of 3 Players, so you can get
- 11 rounds in foursomes (33 opponents)
- 1 round in threesomes (the Last 2 opponents)
And everybody plays everyone ones?
(There's a solution for 24 Players playing 7 foursomes and ohne threesome and every Other Player ones)
Thank you