Round Robin Tournament Scheduling

Schedule balancing over multiple seasons

CentralBlue · 3 · 4128

CentralBlue

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on: January 27, 2009, 10:34:37 PM
The Challenge: 10 teams  max of 16 rounds in a season. 9 rounds = everybody playing each other once.
Goal: Every team plays every other an equal number of times (3) over the coarse of two seasons.

Last season we had 13 rounds every team played the others once and 4 of the teams 2 twice.
So this season there should be 14 rounds as every team plays the others once and the remaining 5 teams twice

I can not seam to get the schedule to work.  Kind of stumped.

here is what I have.

So - here are the teams that need to play each other twice this season in order for every team to have played each other 3 times over the two years.

10 plays - 2,4,6,8,9
9 plays - 1,3,5,7,10
8 plays - 2,4,6,7,10
7 plays - 1,3,5,8,9
6 plays - 2,4,7,8,10
5 plays - 1,3,6,7,9
4 plays - 2,3,6,8,10
3 plays - 1,4,5,7,9
2 plays - 1,4,6,8,10
1 plays - 2,3,5,7,9

Can it be done??


Ian Wakeling

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Reply #1 on: February 01, 2009, 06:29:34 AM
Would you please post the schedule that you played for the first 13 rounds.

I am not sure the list of matches to be played twice is correct.  Shouldn't it be symmetrical?  For example it says that team 5 should play 6, but team 6 does not play 5.


CentralBlue

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Reply #2 on: February 01, 2009, 11:57:20 AM
You are correct it was an typo, probably occur when I copied from the piece of paper I had written it on. Actually figured the problem out. the solution is.

Round 10  2-4  8-6  1-3  7-5  9-0

Round 11  6-2  4-0  5-1  3-9  8-7

Round 12  2-0  4-8  1-9  3-7  5-6

Round 13  8-2  0-6  7-1  9-5  4-3

Round 14  6-4  0-8  5-3  9-7  1-2

Thanks